{"id":515,"date":"2022-01-24T09:19:43","date_gmt":"2022-01-24T08:19:43","guid":{"rendered":"https:\/\/wiskunst.hjgsoft.nl\/?page_id=515"},"modified":"2022-01-24T09:19:43","modified_gmt":"2022-01-24T08:19:43","slug":"oplossing-raadsel-6","status":"publish","type":"page","link":"https:\/\/wiskunst.nl\/index.php\/raadseltjes\/oplossing-raadsel-6\/","title":{"rendered":"Oplossing raadsel 6"},"content":{"rendered":"

Stel we noemen de eerste vaas\u00a0“vaas 1”<\/i>, en de tweede vaas\u00a0“vaas 2”<\/i>, hoe origineel.<\/p>\n

Stop nu in\u00a0“vaas 1”<\/i>\u00a0precies 1 rode knikker en in\u00a0“vaas 2”<\/i>\u00a0alle overige knikkers (dus 100 groene en 99 rode).<\/p>\n

Als de vrouw nu een knikker uit\u00a0“vaas 1”<\/i>\u00a0pakt is de kans dat dit een rode is gelijk aan 1 (=100%).<\/p>\n

Pakt de vrouw daarentegen een knikker uit\u00a0“vaas 2”<\/i>, dan is de kans op een rode gelijk aan 99\/199 (\u00bb49,75%).<\/p>\n

Dit is verreweg de beste verdeling!<\/p>\n","protected":false},"excerpt":{"rendered":"

Stel we noemen de eerste vaas\u00a0“vaas 1”, en de tweede vaas\u00a0“vaas 2”, hoe origineel. Stop nu in\u00a0“vaas 1”\u00a0precies 1 rode knikker en in\u00a0“vaas 2”\u00a0alle overige knikkers (dus 100 groene en 99 rode). Als de vrouw nu een knikker uit\u00a0“vaas 1”\u00a0pakt is de kans dat dit een rode is gelijk aan 1 (=100%). Pakt de vrouw […]<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":499,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"templates\/template-full-width.php","meta":{"_lmt_disableupdate":"","_lmt_disable":"","footnotes":""},"class_list":["post-515","page","type-page","status-publish","hentry"],"yoast_head":"\nOplossing raadsel 6 - Wiskunst<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/wiskunst.nl\/index.php\/raadseltjes\/oplossing-raadsel-6\/\" \/>\n<meta property=\"og:locale\" content=\"nl_NL\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Oplossing raadsel 6 - Wiskunst\" \/>\n<meta property=\"og:description\" content=\"Stel we noemen de eerste vaas\u00a0“vaas 1”, en de tweede vaas\u00a0“vaas 2”, hoe origineel. Stop nu in\u00a0“vaas 1”\u00a0precies 1 rode knikker en in\u00a0“vaas 2”\u00a0alle overige knikkers (dus 100 groene en 99 rode). Als de vrouw nu een knikker uit\u00a0“vaas 1”\u00a0pakt is de kans dat dit een rode is gelijk aan 1 (=100%). 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Stop nu in\u00a0“vaas 1”\u00a0precies 1 rode knikker en in\u00a0“vaas 2”\u00a0alle overige knikkers (dus 100 groene en 99 rode). Als de vrouw nu een knikker uit\u00a0“vaas 1”\u00a0pakt is de kans dat dit een rode is gelijk aan 1 (=100%). 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